TSTP Solution File: NUM691^1 by Duper---1.0

View Problem - Process Solution

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% File     : Duper---1.0
% Problem  : NUM691^1 : TPTP v8.1.2. Released v3.7.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n009.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 10:57:04 EDT 2023

% Result   : Theorem 5.79s 5.99s
% Output   : Proof 5.86s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.11  % Problem    : NUM691^1 : TPTP v8.1.2. Released v3.7.0.
% 0.06/0.12  % Command    : duper %s
% 0.11/0.33  % Computer : n009.cluster.edu
% 0.11/0.33  % Model    : x86_64 x86_64
% 0.11/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.11/0.33  % Memory   : 8042.1875MB
% 0.11/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.11/0.33  % CPULimit   : 300
% 0.11/0.33  % WCLimit    : 300
% 0.11/0.33  % DateTime   : Fri Aug 25 11:18:06 EDT 2023
% 0.11/0.33  % CPUTime    : 
% 5.79/5.99  SZS status Theorem for theBenchmark.p
% 5.79/5.99  SZS output start Proof for theBenchmark.p
% 5.79/5.99  Clause #0 (by assumption #[]): Eq (Not (more x y) → Eq x y) True
% 5.79/5.99  Clause #1 (by assumption #[]): Eq (Not (more z u) → Eq z u) True
% 5.79/5.99  Clause #3 (by assumption #[]): Eq (∀ (Xx Xy Xz Xu : nat), (Not (more Xx Xy) → Eq Xx Xy) → more Xz Xu → more (pl Xx Xz) (pl Xy Xu)) True
% 5.79/5.99  Clause #4 (by assumption #[]): Eq (∀ (Xx Xy Xz Xu : nat), more Xx Xy → (Not (more Xz Xu) → Eq Xz Xu) → more (pl Xx Xz) (pl Xy Xu)) True
% 5.79/5.99  Clause #5 (by assumption #[]): Eq (Not (Not (more (pl x z) (pl y u)) → Eq (pl x z) (pl y u))) True
% 5.79/5.99  Clause #10 (by clausification #[1]): Or (Eq (Not (more z u)) False) (Eq (Eq z u) True)
% 5.79/5.99  Clause #11 (by clausification #[10]): Or (Eq (Eq z u) True) (Eq (more z u) True)
% 5.79/5.99  Clause #12 (by clausification #[11]): Or (Eq (more z u) True) (Eq z u)
% 5.79/5.99  Clause #13 (by clausification #[0]): Or (Eq (Not (more x y)) False) (Eq (Eq x y) True)
% 5.79/5.99  Clause #14 (by clausification #[13]): Or (Eq (Eq x y) True) (Eq (more x y) True)
% 5.79/5.99  Clause #15 (by clausification #[14]): Or (Eq (more x y) True) (Eq x y)
% 5.79/5.99  Clause #16 (by clausification #[5]): Eq (Not (more (pl x z) (pl y u)) → Eq (pl x z) (pl y u)) False
% 5.79/5.99  Clause #17 (by clausification #[16]): Eq (Not (more (pl x z) (pl y u))) True
% 5.79/5.99  Clause #18 (by clausification #[16]): Eq (Eq (pl x z) (pl y u)) False
% 5.79/5.99  Clause #19 (by clausification #[17]): Eq (more (pl x z) (pl y u)) False
% 5.79/5.99  Clause #20 (by clausification #[18]): Ne (pl x z) (pl y u)
% 5.79/5.99  Clause #21 (by clausification #[3]): ∀ (a : nat), Eq (∀ (Xy Xz Xu : nat), (Not (more a Xy) → Eq a Xy) → more Xz Xu → more (pl a Xz) (pl Xy Xu)) True
% 5.79/5.99  Clause #22 (by clausification #[21]): ∀ (a a_1 : nat), Eq (∀ (Xz Xu : nat), (Not (more a a_1) → Eq a a_1) → more Xz Xu → more (pl a Xz) (pl a_1 Xu)) True
% 5.79/5.99  Clause #23 (by clausification #[22]): ∀ (a a_1 a_2 : nat), Eq (∀ (Xu : nat), (Not (more a a_1) → Eq a a_1) → more a_2 Xu → more (pl a a_2) (pl a_1 Xu)) True
% 5.79/5.99  Clause #24 (by clausification #[23]): ∀ (a a_1 a_2 a_3 : nat), Eq ((Not (more a a_1) → Eq a a_1) → more a_2 a_3 → more (pl a a_2) (pl a_1 a_3)) True
% 5.79/5.99  Clause #25 (by clausification #[24]): ∀ (a a_1 a_2 a_3 : nat),
% 5.79/5.99    Or (Eq (Not (more a a_1) → Eq a a_1) False) (Eq (more a_2 a_3 → more (pl a a_2) (pl a_1 a_3)) True)
% 5.79/5.99  Clause #26 (by clausification #[25]): ∀ (a a_1 a_2 a_3 : nat), Or (Eq (more a a_1 → more (pl a_2 a) (pl a_3 a_1)) True) (Eq (Not (more a_2 a_3)) True)
% 5.79/5.99  Clause #27 (by clausification #[25]): ∀ (a a_1 a_2 a_3 : nat), Or (Eq (more a a_1 → more (pl a_2 a) (pl a_3 a_1)) True) (Eq (Eq a_2 a_3) False)
% 5.79/5.99  Clause #28 (by clausification #[26]): ∀ (a a_1 a_2 a_3 : nat),
% 5.79/5.99    Or (Eq (Not (more a a_1)) True) (Or (Eq (more a_2 a_3) False) (Eq (more (pl a a_2) (pl a_1 a_3)) True))
% 5.79/5.99  Clause #29 (by clausification #[28]): ∀ (a a_1 a_2 a_3 : nat),
% 5.79/5.99    Or (Eq (more a a_1) False) (Or (Eq (more (pl a_2 a) (pl a_3 a_1)) True) (Eq (more a_2 a_3) False))
% 5.79/5.99  Clause #30 (by superposition #[29, 12]): ∀ (a a_1 : nat), Or (Eq (more (pl a z) (pl a_1 u)) True) (Or (Eq (more a a_1) False) (Or (Eq False True) (Eq z u)))
% 5.79/5.99  Clause #32 (by clausification #[4]): ∀ (a : nat), Eq (∀ (Xy Xz Xu : nat), more a Xy → (Not (more Xz Xu) → Eq Xz Xu) → more (pl a Xz) (pl Xy Xu)) True
% 5.79/5.99  Clause #33 (by clausification #[32]): ∀ (a a_1 : nat), Eq (∀ (Xz Xu : nat), more a a_1 → (Not (more Xz Xu) → Eq Xz Xu) → more (pl a Xz) (pl a_1 Xu)) True
% 5.79/5.99  Clause #34 (by clausification #[33]): ∀ (a a_1 a_2 : nat), Eq (∀ (Xu : nat), more a a_1 → (Not (more a_2 Xu) → Eq a_2 Xu) → more (pl a a_2) (pl a_1 Xu)) True
% 5.79/5.99  Clause #35 (by clausification #[34]): ∀ (a a_1 a_2 a_3 : nat), Eq (more a a_1 → (Not (more a_2 a_3) → Eq a_2 a_3) → more (pl a a_2) (pl a_1 a_3)) True
% 5.79/5.99  Clause #36 (by clausification #[35]): ∀ (a a_1 a_2 a_3 : nat),
% 5.79/5.99    Or (Eq (more a a_1) False) (Eq ((Not (more a_2 a_3) → Eq a_2 a_3) → more (pl a a_2) (pl a_1 a_3)) True)
% 5.79/5.99  Clause #37 (by clausification #[36]): ∀ (a a_1 a_2 a_3 : nat),
% 5.79/5.99    Or (Eq (more a a_1) False) (Or (Eq (Not (more a_2 a_3) → Eq a_2 a_3) False) (Eq (more (pl a a_2) (pl a_1 a_3)) True))
% 5.79/5.99  Clause #39 (by clausification #[37]): ∀ (a a_1 a_2 a_3 : nat),
% 5.86/6.02    Or (Eq (more a a_1) False) (Or (Eq (more (pl a a_2) (pl a_1 a_3)) True) (Eq (Eq a_2 a_3) False))
% 5.86/6.02  Clause #43 (by clausification #[27]): ∀ (a a_1 a_2 a_3 : nat),
% 5.86/6.02    Or (Eq (Eq a a_1) False) (Or (Eq (more a_2 a_3) False) (Eq (more (pl a a_2) (pl a_1 a_3)) True))
% 5.86/6.02  Clause #44 (by clausification #[43]): ∀ (a a_1 a_2 a_3 : nat), Or (Eq (more a a_1) False) (Or (Eq (more (pl a_2 a) (pl a_3 a_1)) True) (Ne a_2 a_3))
% 5.86/6.02  Clause #45 (by destructive equality resolution #[44]): ∀ (a a_1 a_2 : nat), Or (Eq (more a a_1) False) (Eq (more (pl a_2 a) (pl a_2 a_1)) True)
% 5.86/6.02  Clause #46 (by superposition #[45, 12]): ∀ (a : nat), Or (Eq (more (pl a z) (pl a u)) True) (Or (Eq False True) (Eq z u))
% 5.86/6.02  Clause #52 (by clausification #[46]): ∀ (a : nat), Or (Eq (more (pl a z) (pl a u)) True) (Eq z u)
% 5.86/6.02  Clause #61 (by clausification #[30]): ∀ (a a_1 : nat), Or (Eq (more (pl a z) (pl a_1 u)) True) (Or (Eq (more a a_1) False) (Eq z u))
% 5.86/6.02  Clause #63 (by superposition #[61, 15]): Or (Eq (more (pl x z) (pl y u)) True) (Or (Eq z u) (Or (Eq False True) (Eq x y)))
% 5.86/6.02  Clause #66 (by clausification #[63]): Or (Eq (more (pl x z) (pl y u)) True) (Or (Eq z u) (Eq x y))
% 5.86/6.02  Clause #67 (by superposition #[66, 19]): Or (Eq z u) (Or (Eq x y) (Eq True False))
% 5.86/6.02  Clause #73 (by clausification #[67]): Or (Eq z u) (Eq x y)
% 5.86/6.02  Clause #74 (by superposition #[73, 19]): Or (Eq z u) (Eq (more (pl y z) (pl y u)) False)
% 5.86/6.02  Clause #76 (by superposition #[74, 52]): Or (Eq z u) (Or (Eq False True) (Eq z u))
% 5.86/6.02  Clause #77 (by clausification #[76]): Or (Eq z u) (Eq z u)
% 5.86/6.02  Clause #78 (by eliminate duplicate literals #[77]): Eq z u
% 5.86/6.02  Clause #80 (by backward demodulation #[78, 19]): Eq (more (pl x u) (pl y u)) False
% 5.86/6.02  Clause #81 (by backward demodulation #[78, 20]): Ne (pl x u) (pl y u)
% 5.86/6.02  Clause #87 (by clausification #[39]): ∀ (a a_1 a_2 a_3 : nat), Or (Eq (more a a_1) False) (Or (Eq (more (pl a a_2) (pl a_1 a_3)) True) (Ne a_2 a_3))
% 5.86/6.02  Clause #88 (by destructive equality resolution #[87]): ∀ (a a_1 a_2 : nat), Or (Eq (more a a_1) False) (Eq (more (pl a a_2) (pl a_1 a_2)) True)
% 5.86/6.02  Clause #89 (by superposition #[88, 15]): ∀ (a : nat), Or (Eq (more (pl x a) (pl y a)) True) (Or (Eq False True) (Eq x y))
% 5.86/6.02  Clause #96 (by clausification #[89]): ∀ (a : nat), Or (Eq (more (pl x a) (pl y a)) True) (Eq x y)
% 5.86/6.02  Clause #97 (by superposition #[96, 80]): Or (Eq x y) (Eq True False)
% 5.86/6.02  Clause #103 (by clausification #[97]): Eq x y
% 5.86/6.02  Clause #110 (by backward positive simplify reflect #[103, 81]): False
% 5.86/6.02  SZS output end Proof for theBenchmark.p
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